pre decrement struct single pointer ==================================== In this section, you are going to learn .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow How to iterate structure array using --ptr ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow What is the meaning of ``--ptr``, ``*--ptr``, ``*(--ptr)``, ``*--(ptr)``, ``--(*ptr)``, ``--*ptr`` ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow What is the meaning of ``c = --ptr``, ``c = *--ptr``, ``c = *(--ptr)``, ``c = *--(ptr)``, ``c = --(*ptr)``, ``c = --*ptr`` ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow What is the difference between ``--ptr``, ``*--ptr``, ``*(--ptr)``, ``*--(ptr)``, ``--(*ptr)``, ``--*ptr`` ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow What is the difference between ``c = --ptr``, ``c = *--ptr``, ``c = *(--ptr)``, ``c = *--(ptr)``, ``c = --(*ptr)``, ``c = --*ptr`` ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Topics of Pre Decrement * :ref:`Basics of Pre Decrement ` * :ref:`Meaning of expressions ` * :ref:`Summary of expressions ` * :ref:`Pre Decrement : struct pointer inside structure ` * :ref:`Pre Decrement : Function Call ` .. _post_decr_struct_sp_mt_1: .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Basics of Pre Decrement * :ref:`--ptr Basic Usage ` * :ref:`--ptr : Iterate and print structures of an structure array ` .. _post_decr_struct_sp_ex_1: .. tab-set:: .. tab-item:: Example 1 : ``--ptr`` : Basic Usage * Step 1 : Define a Single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Point ``ptr`` to Single dimension array .. code-block:: c struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]) - 1; * Step 3 : Decrement ``ptr`` .. code-block:: c --ptr; * Step 4 : Print ``*ptr`` .. code-block:: c printf("ptr->a = %d\n", ptr->a); printf("ptr->b = %d\n", ptr->b); * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]) - 1; --ptr; printf("ptr->a = %d\n", ptr->a); printf("ptr->b = %d\n", ptr->b); return 0; } * Output is as below .. code-block:: c ptr->a = 2 ptr->b = 3 .. _post_decr_struct_sp_ex_2: .. tab-set:: .. tab-item:: Example 2 : ``--ptr`` : Iterate and print structures of an structure array * Step 1 : Define a Single Dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Point ``ptr`` to Single dimension array .. code-block:: c struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]) - 1; * Step 3 : Print structure array by iterating through all structures using ``--ptr`` .. code-block:: c for (int i = 0; i < 3; i++) { printf("ptr->a = %d\n", ptr->a); printf("ptr->b = %d\n", ptr->b); --ptr; } * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]) - 1; for (int i = 0; i < 3; i++) { printf("ptr->a = %d\n", ptr->a); printf("ptr->b = %d\n", ptr->b); --ptr; } return 0; } * Output is as below .. code-block:: c ptr->a = 4 ptr->b = 5 ptr->a = 2 ptr->b = 3 ptr->a = 0 ptr->b = 1 .. _post_decr_struct_sp_mt_2: .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Meaning of expressions * :ref:`Meaning of --ptr and c = --ptr ` * :ref:`Meaning of *(--ptr) and c = *(--ptr) ` * :ref:`Meaning of *--ptr and c = *--ptr ` * :ref:`Meaning of *--(ptr) and c = *--(ptr) ` * :ref:`Meaning of --(*ptr) and c = --(*ptr) ` .. _post_decr_struct_sp_ex_6: .. tab-set:: .. tab-item:: Meaning of ``--ptr`` and ``c = --ptr`` .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Consider statement .. code-block:: c p = --ptr; * There are two steps in this statement * ``ptr`` is decremented * Current value of ``ptr`` is assigned to ``p`` * We now derived a rule * First Decrement, then Assign * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Define a single pointer and point to array .. code-block:: c struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); OR .. code-block:: c struct User_Data *ptr; ptr = &arr[0] + sizeof(arr)/sizeof(arr[0]); * Step 3 : Iterate and print the structure array .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data *p; p = --ptr; printf("p->a = %d\n", p->a); printf("p->b = %d\n", p->b); } .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Can you guess what is happening ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Let us Recall .. code-block:: c p = --ptr; * There are two steps in this statement * ``ptr`` is decremented * Current value of ``ptr`` is assigned to ``p`` * We now derived a rule * First Decrement, then Assign * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data *p; p = --ptr; printf("p->a = %d\n", p->a); printf("p->b = %d\n", p->b); } return 0; } * Output is as below .. code-block:: c p->a = 4 p->b = 5 p->a = 2 p->b = 3 p->a = 0 p->b = 1 .. _post_decr_struct_sp_ex_7: .. tab-set:: .. tab-item:: Meaning of ``*(--ptr)`` and ``c = *(--ptr)`` .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Consider statement .. code-block:: c c = *(--ptr); * There are two steps in this statement * ``ptr`` is decremented * Current value of ``*ptr`` is assigned to ``c`` * ``*ptr`` is NOT decremented * We now derived a rule * First Decrement, then Assign * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Define a single pointer and point to array .. code-block:: c struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); OR .. code-block:: c struct User_Data *ptr; ptr = &arr[0] + sizeof(arr)/sizeof(arr[0]); * Step 3 : Iterate and print the structure array .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *(--ptr); printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } Output is as below .. code-block:: c .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Can you guess what is happening ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Let us Recall .. code-block:: c c = *(--ptr); * There are two steps in this statement * ``ptr`` is decremented * Current value of ``*ptr`` is assigned to ``c`` * ``*ptr`` is NOT decremented * We now derived a rule * First Decrement, then Assign * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *(--ptr); printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_10: .. tab-set:: .. tab-item:: Meaning of ``*--ptr`` and c = ``*--ptr`` .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * :ref:`Same as *(--ptr) and c = *(--ptr) ` .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Consider statement .. code-block:: c c = *--ptr; * There are two steps in this statement * ``ptr`` is decremented * Current value of ``*ptr`` is assigned to ``c`` * ``*ptr`` is NOT decremented * We now derived a rule * First Decrement, then Assign * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Define a single pointer and point to array .. code-block:: c struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); OR .. code-block:: c struct User_Data *ptr; ptr = &arr[0] + sizeof(arr)/sizeof(arr[0]); * Step 3 : Iterate and print the structure array .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Can you guess what is happening ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Let us Recall .. code-block:: c c = *--ptr; * There are two steps in this statement * ``ptr`` is decremented * Current value of ``*ptr`` is assigned to ``c`` * ``*ptr`` is NOT decremented * We now derived a rule * First Decrement, then Assign * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_8: .. tab-set:: .. tab-item:: Meaning of ``*--(ptr)`` and ``c = *--(ptr)`` .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * :ref:`Same as *(--ptr) and c = *(--ptr) ` .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Consider statement .. code-block:: c c = *--(ptr); * There are two steps in this statement * ``ptr`` is decremented * Current value of ``*ptr`` is assigned to ``c`` * ``*ptr`` is NOT decremented * We now derived a rule * First Decrement, then Assign * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Define a single pointer and point to array .. code-block:: c struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); OR .. code-block:: c struct User_Data *ptr; ptr = &arr[0] + sizeof(arr)/sizeof(arr[0]); * Step 3 : Iterate and print the structure array .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--(ptr); printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Can you guess what is happening ? .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Let us Recall .. code-block:: c c = *--(ptr); * There are two steps in this statement * ``ptr`` is decremented * Current value of ``*ptr`` is assigned to ``c`` * ``*ptr`` is NOT decremented * We now derived a rule * First Decrement, then Assign * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--(ptr); printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_9: .. tab-set:: .. tab-item:: Meaning of ``--(*ptr)`` and ``c = --(*ptr)`` .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow * Consider statement .. code-block:: c c = --(*ptr); * This is invalid usage for a structure pointer ! .. _post_decr_struct_sp_mt_3: .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Summary of expressions * :ref:`Summary of Pre Decrement expressions ` .. _post_decr_struct_sp_ex_summary: .. tab-set:: .. tab-item:: Summary of Pre Decrement expressions ===================================== ========================================================================= Expression Explanation ===================================== ========================================================================= c = --ptr * Decrement ``ptr`` * Assign ``ptr`` to ``c`` c = \*--ptr * Decrement ``ptr`` * Assign ``*ptr`` to ``c`` * DO NOT decrement ``*ptr`` c = \*(--ptr) * Decrement ``ptr`` * Assign ``*ptr`` to ``c`` * DO NOT decrement ``*ptr`` c = \*--(ptr) * Decrement ``ptr`` * Assign ``*ptr`` to ``c`` * DO NOT decrement ``*ptr`` c = --\*ptr * INVALID for structure pointer c = --\*(ptr) * INVALID for structure pointer ===================================== ========================================================================= .. _post_decr_struct_sp_mt_4: .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Pre Decrement : struct pointer inside structure * :ref:`Structure pointer accessed using Structure Object ` * :ref:`Structure pointer accessed using Structure Single Pointer ` * :ref:`Structure pointer accessed using Structure Double Pointer ` * :ref:`Structure pointer accessed using Structure Triple Pointer ` * :ref:`Structure pointer accessed using Nested Structure Object ` * :ref:`Structure pointer accessed using Nested Structure Single Pointer ` * :ref:`Structure pointer accessed using Nested Structure 2 level Pointers ` .. _post_decr_struct_sp_ex_struct_ex_1: .. tab-set:: .. tab-item:: Structure pointer accessed using Structure Object * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Create a structure object .. code-block:: c struct ABC { struct User_Data *ptr; }; struct ABC abc; * Step 3 : Point single structure pointer to single dimension array .. code-block:: c abc.ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 4 : Iterate through single dimension array using pointer .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--abc.ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; struct ABC { struct User_Data *ptr; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct ABC abc; abc.ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--abc.ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_struct_ex_2: .. tab-set:: .. tab-item:: Structure pointer accessed using Structure Single Pointer * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Allocate memory for structure pointers .. code-block:: c struct ABC { struct User_Data *ptr; }; struct ABC *sp; sp = malloc(sizeof(struct ABC)); * Step 3 : Point single structure pointer to single dimension array .. code-block:: c sp->ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 4 : Iterate through single dimension array using pointer .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--sp->ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } * Step 5 : Free memory after use .. code-block:: c free(sp); * See full program below .. code-block:: c #include #include struct User_Data { int a; int b; }; struct ABC { struct User_Data *ptr; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct ABC *sp; sp = malloc(sizeof(struct ABC)); sp->ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--sp->ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } free(sp); return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_struct_ex_3: .. tab-set:: .. tab-item:: Structure pointer accessed using Structure Double Pointer * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Allocate memory for structure pointers .. code-block:: c struct ABC { struct User_Data *ptr; }; struct ABC **dp; dp = malloc(sizeof(struct ABC *)); *dp = malloc(sizeof(struct ABC )); * Step 3 : Point single structure pointer to single dimension array .. code-block:: c (*dp)->ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 4 : Iterate through single dimension array using pointer .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--(*dp)->ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } * Step 5 : Free memory after use .. code-block:: c free(*dp); free(dp); * See full program below .. code-block:: c #include #include struct User_Data { int a; int b; }; struct ABC { struct User_Data *ptr; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct ABC **dp; dp = malloc(sizeof(struct ABC *)); *dp = malloc(sizeof(struct ABC )); (*dp)->ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--(*dp)->ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } free(*dp); free(dp); return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_struct_ex_4: .. tab-set:: .. tab-item:: Structure pointer accessed using Structure Triple Pointer * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Allocate memory for structure pointers .. code-block:: c struct ABC { struct User_Data *ptr; }; struct ABC ***dp; dp = malloc(sizeof(struct ABC **)); *dp = malloc(sizeof(struct ABC *)); **dp = malloc(sizeof(struct ABC )); * Step 3 : Point single structure pointer to single dimension array .. code-block:: c (**dp)->ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 4 : Iterate through single dimension array using pointer .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--(**dp)->ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } * Step 5 : Free memory after use .. code-block:: c free(**dp); free(*dp); free(dp); * See full program below .. code-block:: c #include #include struct User_Data { int a; int b; }; struct ABC { struct User_Data *ptr; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct ABC ***dp; dp = malloc(sizeof(struct ABC **)); *dp = malloc(sizeof(struct ABC *)); **dp = malloc(sizeof(struct ABC )); (**dp)->ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--(**dp)->ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } free(**dp); free(*dp); free(dp); return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_struct_ex_5: .. tab-set:: .. tab-item:: Structure pointer accessed using Nested Structure Object * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Create a structure object .. code-block:: c struct PQR { struct User_Data *ptr; }; struct ABC { struct PQR pqr; }; struct ABC abc; * Step 3 : Point single structure pointer to single dimension array .. code-block:: c abc.pqr.ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 4 : Iterate through single dimension array using pointer .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--abc.pqr.ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; struct PQR { struct User_Data *ptr; }; struct ABC { struct PQR pqr; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct ABC abc; abc.pqr.ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--abc.pqr.ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_struct_ex_6: .. tab-set:: .. tab-item:: Structure pointer accessed using Nested Structure Single Pointer * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Allocate memory for structure pointers .. code-block:: c struct PQR { struct User_Data *ptr; }; struct ABC { struct PQR pqr; }; struct ABC *sp; sp = malloc(sizeof(struct ABC)); * Step 3 : Point single structure pointer to single dimension array .. code-block:: c sp->pqr.ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 4 : Iterate through single dimension array using pointer .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--sp->pqr.ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } * Step 5 : Free memory after use .. code-block:: c free(sp); * See full program below .. code-block:: c #include #include struct User_Data { int a; int b; }; struct PQR { struct User_Data *ptr; }; struct ABC { struct PQR pqr; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct ABC *sp; sp = malloc(sizeof(struct ABC)); sp->pqr.ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--sp->pqr.ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } free(sp); return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_ex_struct_ex_7: .. tab-set:: .. tab-item:: Structure pointer accessed using Nested Structure 2 level Pointers * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Allocate memory for structure pointers .. code-block:: c struct PQR { struct User_Data *ptr; }; struct ABC { struct PQR *pqr; }; struct ABC *abc; abc = malloc(sizeof(struct ABC)); abc->pqr = malloc(sizeof(struct PQR)); * Step 3 : Point single structure pointer to single dimension array .. code-block:: c abc->pqr->ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 4 : Iterate through single dimension array using pointer .. code-block:: c for (int i = 0; i < 3; i++) { struct User_Data c; c = *--abc->pqr->ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } * Step 5 : Free memory after use .. code-block:: c free(abc->pqr); free(abc); * See full program below .. code-block:: c #include #include struct User_Data { int a; int b; }; struct PQR { struct User_Data *ptr; }; struct ABC { struct PQR *pqr; }; int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct ABC *abc; abc = malloc(sizeof(struct ABC)); abc->pqr = malloc(sizeof(struct PQR)); abc->pqr->ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { struct User_Data c; c = *--abc->pqr->ptr; printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } free(abc->pqr); free(abc); return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_mt_5: .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Pre Decrement : Function Call * :ref:`*--ptr : Function Call ` * :ref:`--ptr : Function Call ` .. _post_decr_struct_sp_call_by_value_ex_1: .. tab-set:: .. tab-item:: \*--ptr : Function Call * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Define a single pointer and point to array .. code-block:: c struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 3 : Iterate array using --ptr and Pass by Value .. code-block:: c for (int i = 0; i < 3; i++) { fun(*--ptr); } * Step 4 : Define a function ``fun`` which receives a structure from caller .. code-block:: c void fun(struct User_Data c) { printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Let us Recall, * In case of ``*--ptr`` * ``ptr`` is decremented first, then current value of ``*ptr`` is assigned * Hence, in this case * ``ptr`` is decremented first, then current value of ``*ptr`` is passed as arguement to function ``fun`` * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; void fun(struct User_Data c) { printf("c.a = %d\n", c.a); printf("c.b = %d\n", c.b); } int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { fun(*--ptr); } return 0; } * Output is as below .. code-block:: c c.a = 4 c.b = 5 c.a = 2 c.b = 3 c.a = 0 c.b = 1 .. _post_decr_struct_sp_call_by_value_ex_2: .. tab-set:: .. tab-item:: --ptr : Function Call * Step 1 : Define a single dimension array .. code-block:: c struct User_Data { int a; int b; }; struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; * Step 2 : Define a single pointer and point to array .. code-block:: c struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); * Step 3 : Iterate array using --ptr and Pass by Value .. code-block:: c for (int i = 0; i < 3; i++) { fun(--ptr); } * Step 4 : Define a function ``fun`` which receives a structure pointer from caller .. code-block:: c void fun(struct User_Data *c) { printf("c->a = %d\n", c->a); printf("c->b = %d\n", c->b); } .. panels:: :container: container pb-4 :column: col-lg-12 p-2 :card: shadow Let us Recall, * In case of ``--ptr`` * `ptr`` is first decremented, then assigned * Hence, in this case * `ptr`` is first decremented, then current value of ``ptr`` is assigned as argument to function ``fun`` * See full program below .. code-block:: c #include struct User_Data { int a; int b; }; void fun(struct User_Data *c) { printf("c->a = %d\n", c->a); printf("c->b = %d\n", c->b); } int main(void) { struct User_Data arr[3] = { { .a = 0, .b = 1 }, { .a = 2, .b = 3 }, { .a = 4, .b = 5 }, }; struct User_Data *ptr; ptr = arr + sizeof(arr)/sizeof(arr[0]); for (int i = 0; i < 3; i++) { fun(--ptr); } return 0; } * Output is as below .. code-block:: c c->a = 4 c->b = 5 c->a = 2 c->b = 3 c->a = 0 c->b = 1 .. card:: See Also * Current Module * :doc:`../pre_decr_ptr` * Previous Module * :doc:`../../post_incr_ptr/post_incr_ptr` * Next Module * :doc:`../../post_decr_ptr/post_decr_ptr` * Other Modules * :doc:`../../variable_and_ptr/variable_and_ptr` * :doc:`../../array_n_ptrs/array_n_ptrs` * :doc:`../../malloc_ptr/malloc_ptr` * :doc:`../../typecasting_n_ptr/typecasting_n_ptr` * :doc:`../../funcs_n_ptrs/funcs_n_ptrs` * :doc:`../../memcpy_ptr/memcpy_ptr` * :doc:`../../const_ptr/const_ptr` * :doc:`../../void_ptr/void_ptr` * :doc:`../../array_of_ptr/array_of_ptr` * :doc:`../../ptr_to_array/ptr_to_array` * :doc:`../../pre_incr_ptr/pre_incr_ptr`